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0.1x^2-1.1x-1=0
a = 0.1; b = -1.1; c = -1;
Δ = b2-4ac
Δ = -1.12-4·0.1·(-1)
Δ = 1.61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.1)-\sqrt{1.61}}{2*0.1}=\frac{1.1-\sqrt{1.61}}{0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.1)+\sqrt{1.61}}{2*0.1}=\frac{1.1+\sqrt{1.61}}{0.2} $
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